How to convert a char array into an int in C++?

C++ problem: I have a char's array containing a number that I want to move to an int, how do I do that?

• example... int a; char b[3]='123'; //(I dunno if this is even possible but the fact is I have a char array containing a many digits number) a=b; how do I do this?

• Answer:

  Okay, you can't store the sting in a char, but you can store it in an array of char[]; the syntax you are looking for is atoi int i = atoi("123"); #include <stdio.h> #include <stdlib.h> int main () { int i; char szInput [256]; printf ("Enter a number: "); fgets ( szInput, 256, stdin ); i = atoi (szInput); printf ("The value entered is %d. The double is %d.\n",i,i*2); return 0; }