How to pass char** in python ctype?

Confused on how to pass char *argv[]?

• Im need to check if argv[1] is a number but im not sure how to pas it to a function to check with is digit. This is what I have right now. bool is_legal(char *argv[]) { for(int i = 0; argv[i]; i++) if(!isdigit(argv[i])) { cerr << "Error: invalid number of checkers specified."; return 1; } return 0; } and im passing is_legal(argv[1]);

• Answer:

  If you are simply passing one variable within the array index, then you function implementation "is_legal" doesnt need the * "argv" is a 2-D array of chars, but when you declare your function declaration like this "is_legal(argv[1]);" ^ you are now passing a one dimensional array to a function, because "argv[1]" is only one index within that array So your "is_legal" function should look like this __ bool is_legal(char argv[]) { int i=0; while(argv[i]!='\0') { if(!isdigit(argv[i])) { cerr << "Error: invalid number of checkers specified."; return 1; } ++i; } return 0; }