An investor placed a total of $10,000 in two simple interest accounts. one accounts earned a simple interest?
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rate of 5.2%, and the other earned a simple interest rate of of 3.6%. the two accounts earned a total of $488. How much was invested in each accounts?
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Answer:
The 1st account had $5,909 invested at 5.2% for 1.075 years.___ It earned $330.31 The 2nd account had $4,091 invested at 3.60% for 1.075 years__It earned $158.32 5,909.00 5.20% 1.075 330.3131 4,091.00 3.60% 1.075 158.3217 488.6348
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Other answers
Use the famous and (evidently) virtually unknown 2 variable, 2 equation system. A + B = 10,000 .052*A + .036*B = 488. rearrange to deal with one variable, plug in, solve, replace into original formulas, solve
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