How much zinc in grams is required to make 18.8 grams of hydrogen gas through this reaction?

so you just find out the MW of zinc by looking at the periodic chart and it is 65.39 and you set up a gram to mole ratio so 18.8 grams of zn /65.39g of zn *1 mole gives you the moles the mole to mole ratio you get through the equation and it's 1 to 1 so you now have it in terms of moles of hydrogen gas which has a MW of 2 and you multiply the number of moles by the MW of hydrogen... the answer i get is .575 grams of h2 gas ... just set up the problem so the ratios you make will cancel out to get you grams of h2

1 mole of zinc results in 1 mole of hydrogen gas, molar ratios are 1/1 molar mass of zinc = 65.37 grams. molar mass of H2 is 2 grams 18.8 g H2 = 9.4 moles of H2 Now if 65.37 g of Zinc is required to make 1 mole of H2 Then 65.37g Zn (9.4) = 614.478 grams of Zinc are needed to make 18.8 grams of Hydrogen gas.

so you just find out the MW of zinc by looking at the periodic chart and it is 65.39 and you set up a gram to mole ratio so 18.8 grams of zn /65.39g of zn *1 mole gives you the moles the mole to mole ratio you get through the equation and it's 1 to 1 so you now have it in terms of moles of hydrogen gas which has a MW of 2 and you multiply the number of moles by the MW of hydrogen... the answer i get is .575 grams of h2 gas ... just set up the problem so the ratios you make will cancel out to get you grams of h2