A solution is prepared from 0.131 mol of formic acid and enough water to make 0.440 L of solution.?
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a) Determine the concentrations of H3O+ and HCOO ‾ in this solution. H3O+ concentration-->.00711 (correct) HCOO ‾ concentration-->.00711(correct) (b) Determine the H3O+ concentration that would be necessary to decrease the HCOO ‾ concentration above by a factor of ten. How many milliliters of 2.60 M HCl would be required to produce this solution? Consider that the solution was made by combining the HCl, the HCOOH, and enough water to make 0.440 L of solution.
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Answer:
Start out with the equation: HCOOH + H2O < --> COOH- + H3O+ a) Molarity = 0.131/ 0.440 L = [0.298] or 0.298 M b) To obtain a 0.0298 M (decrease of factor of ten or 1/10th of original) M1 x V1= M2 x V2 (0.298)(0.440)/ 0.0298 = V2 = 4.4 liters Add (4.4 - .44 =) 3.96 liters of water to the original solution.
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Start out with the equation: HCOOH + H2O < --> COOH- + H3O+ a) Molarity = 0.131/ 0.440 L = [0.298] or 0.298 M b) To obtain a 0.0298 M (decrease of factor of ten or 1/10th of original) M1 x V1= M2 x V2 (0.298)(0.440)/ 0.0298 = V2 = 4.4 liters Add (4.4 - .44 =) 3.96 liters of water to the original solution.
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