One type of electromagnetic radiation has a frequency of 107.1 MHz,another type has a wavelength of 2.12x 10?
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Answer:
E1=hf = (6*10^-34)*107*10^6 =6*10^-26 (J) f2=C/Lamada=3*10^8/2.12 *10 =15 * 10^6 (Hz) E2=h*f2=(6*10^-34)*15*10^6 =9*10^-27 (J) E3=3.97*10^-19 Therefore, E3 is bigger than E1 E1 is greater than E2
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E1=hf = (6*10^-34)*107*10^6 =6*10^-26 (J) f2=C/Lamada=3*10^8/2.12 *10 =15 * 10^6 (Hz) E2=h*f2=(6*10^-34)*15*10^6 =9*10^-27 (J) E3=3.97*10^-19 Therefore, E3 is bigger than E1 E1 is greater than E2
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