What is the molarity of an aqueous solution containing 40.0g of glucose in 1.5L of solution?

40.0 g/1.5 L = 26.7g/ L since a mole of glucose is 180 g, thats 26.7/180 = 0.148 molar (0.15 molar rounded to 2 significant figures)

Morality = Moles of solute/ Liters of solution The solute in the problem is glucose which is C6H12O6 Since the solute is in grams you need to convert it into moles so 40.0 g x mole /180 g of glucose ( the 180 g of glucose is the molar mass of glucose which is calculated by multiplying the the number of moles given and the elements mass for ex. there are 6 moles of carbon in glucose according to the formula so just multiply 6 to the mass of carbon and then add it to the rest by doing the same) once you get the moles just divide the moles by the liters given and that is the answer 40.0 g x 1 mole /180 g glucose =0.22 Morality = 0.22/1.5= 0.146 M

40.0 g/1.5 L = 26.7g/ L since a mole of glucose is 180 g, thats 26.7/180 = 0.148 molar (0.15 molar rounded to 2 significant figures)