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How to find molar mass of salt including waters of hydration?

  • Using molar mass of the salt(KBr) including waters of hydration, and the mass of salt dissolved to calculate the molar heat? Heat=1910J, mass of KBr dissolved=6.6g, Water=50ml -- I did the experiment in lab, but I don't know how to solve for molar mass of KBr+hydration. I need to get that number then convert into mole and solve for molar heat(which i can find by myself) this lab dues tomorrow, so please help me :(( thanks :)

  • Answer:

    molar mass of KBr = 119 It looks as if you found 1910 J per 6.6 g KBr ? mole KBr = 6.6 g KBr x 1 mole KBr / 119 g KBr = 0.055 mole ? kJ/mole = 1910 J / 0.055 mole = 34000 J/mol = 34 kJ/mol

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molar mass of KBr = 119 It looks as if you found 1910 J per 6.6 g KBr ? mole KBr = 6.6 g KBr x 1 mole KBr / 119 g KBr = 0.055 mole ? kJ/mole = 1910 J / 0.055 mole = 34000 J/mol = 34 kJ/mol

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