Nuclear chem: Calculate energy released when 5 kg of U-235 goes under fission:?
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n + U-235 -> I-136 + Y-96 + 4n n=neutron (1 0) The mass of I nuclei is 135.8401 amu and Y is 95.8629 amu. Neutron is 1.008665 amu Answer: -6.02 x 10^14 J, I want to know process Bonus: Find heat released when 5 kg C (graphite) burns to CO2 (gas) Answer: 1.64 x 10^5 kJ yea...I need some help..THANKS :D
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Answer:
Find the mass defect first. In this case it is 0.271005 amu.(Do the calculations) As E= mc^2 find the energy released.Let it be E J 92 g of U-235 = E j of energy. 5Kg of U-235 = you can calculate. For 2nd question you require heat of combustion of graphite. it is C(graphite) + O2(g) -----------------> CO2(g) dH =- 393.5 kj mol-1 12 g Graphite = 393.5 Kj energy 5Kg graphite = 393.5/12)X 5000 = your answer.
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Find the mass defect first. In this case it is 0.271005 amu.(Do the calculations) As E= mc^2 find the energy released.Let it be E J 92 g of U-235 = E j of energy. 5Kg of U-235 = you can calculate. For 2nd question you require heat of combustion of graphite. it is C(graphite) + O2(g) -----------------> CO2(g) dH =- 393.5 kj mol-1 12 g Graphite = 393.5 Kj energy 5Kg graphite = 393.5/12)X 5000 = your answer.
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