Determine the molarity of a nitric acid solution (HNO3) if 17.8ml of nitric acid solution?
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Answer:
KOH + HNO3 -> KNO3 + H2O Notice the 1:1 ratio of KOH to HNO3? 16ml = .016L .016L x .16M KOH = .00256mol KOH .00256mol KOH x (1mol HNO3/1mol KOH) = .00256mol HNO3 17.8ml = .0178L .00256mol HNO3/.0178L = .14M HNO3
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Other answers
KOH + HNO3 -> KNO3 + H2O Notice the 1:1 ratio of KOH to HNO3? 16ml = .016L .016L x .16M KOH = .00256mol KOH .00256mol KOH x (1mol HNO3/1mol KOH) = .00256mol HNO3 17.8ml = .0178L .00256mol HNO3/.0178L = .14M HNO3
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