When a 4.00-g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 3.418 kJ·?
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Answer:
The heat absorbed by the H2O = (heat capacity calorimeter)(delta T) = (3.418 kJ/K)(0.270 K) = 0.923 kJ 4.00 g KCl x (1 mole KCl / 74.6 g KCl) = 0.0536 moles KCl 0.923 kJ / 0.0536 moles KCl = 17.2 kJ / mole KCl
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Other answers
The heat absorbed by the H2O = (heat capacity calorimeter)(delta T) = (3.418 kJ/K)(0.270 K) = 0.923 kJ 4.00 g KCl x (1 mole KCl / 74.6 g KCl) = 0.0536 moles KCl 0.923 kJ / 0.0536 moles KCl = 17.2 kJ / mole KCl
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