What is the reducing agent and the oxidizing agent in the redox equation SbCl5 + KI → SbCl3 + KCl + I2?
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Answer:
It's A because here sb is reduced from +5 oxidation state to +3 oxidation state. And it is done by KI. So answer no 1 is right.
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Other answers
It's A because here sb is reduced from +5 oxidation state to +3 oxidation state. And it is done by KI. So answer no 1 is right.
Rajendra Kunwar
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