Chemistry Question - How many grams of sucrose must be dissolved in 900mL of water to make 80% (W/W) sucrose?
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Answer:
assume a density of 1 g/ml for H2O. Then 900 ml H2O weigh 900 g 80% = 0.8 x = mass of sucrose 0.8= x/(900+x) 0.8 * 900 + 0.8 * x = x 0.8 * 900 = x - 0.8 * x 0.8 * 900 = 0.2 x 0.8 * 900 / 0.2 = x 3600 = x
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Other answers
assume a density of 1 g/ml for H2O. Then 900 ml H2O weigh 900 g 80% = 0.8 x = mass of sucrose 0.8= x/(900+x) 0.8 * 900 + 0.8 * x = x 0.8 * 900 = x - 0.8 * x 0.8 * 900 = 0.2 x 0.8 * 900 / 0.2 = x 3600 = x
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