What was the molarity of the HCl solution?

HCl + NaOH --> NaCl + H2O (reaction of Titration) Number of Moles of NaOH = 0.1051*37.22 ml / 1000 ml = 0.003911822 mol From reaction : Moles of NaOH = Moles of HCL => Moles of HCL = 0.003911822 mol ~ 0.003912 mol Molarity of HCL = Moles Of HCl / 1 L = (0.003911822 mol * 1000 ml) / (50 ml * 1 L) = = 0.07823644 Mol/L ~ 0.078 mol/L ******************** How many moles of HCl, in the HCl solution were titrated? .... 0.003912 mol What was the molarity of the HCl solution?.... 0.078 mol/L

Well im kinda rusty at this but i believe the answers are .003912 moles of HLC and the molarity of it was .07824. soooo tired.... anyway, lemme explain the logic behind those answers. The moles of HCl have to equal the amount of moles of NaOH cuz thats how it is in a acid base reaction (msg me if you want me to explain that part more). Molarity = Moles/Liters so you have to convert all the mL into L so you have .05 L of HCl and .03722 L of NaOH. Now you are trying to find the number of moles of HCl and that equals the amount of moles of NaOH. You have the Molarity and Liters of NaOH and with that you can find the moles. .1051=X/.03722 X = .003912 So thats the first answer. The second answer you find with the same formula but this time you are putting in .05L and the moles instead of molarity. X = .003912/.05 X=.07824 Thats all you should need to know but if you have questions just contact me.

Well im kinda rusty at this but i believe the answers are .003912 moles of HLC and the molarity of it was .07824. soooo tired.... anyway, lemme explain the logic behind those answers. The moles of HCl have to equal the amount of moles of NaOH cuz thats how it is in a acid base reaction (msg me if you want me to explain that part more). Molarity = Moles/Liters so you have to convert all the mL into L so you have .05 L of HCl and .03722 L of NaOH. Now you are trying to find the number of moles of HCl and that equals the amount of moles of NaOH. You have the Molarity and Liters of NaOH and with that you can find the moles. .1051=X/.03722 X = .003912 So thats the first answer. The second answer you find with the same formula but this time you are putting in .05L and the moles instead of molarity. X = .003912/.05 X=.07824 Thats all you should need to know but if you have questions just contact me.

HCl + NaOH --> NaCl + H2O (reaction of Titration) Number of Moles of NaOH = 0.1051*37.22 ml / 1000 ml = 0.003911822 mol From reaction : Moles of NaOH = Moles of HCL => Moles of HCL = 0.003911822 mol ~ 0.003912 mol Molarity of HCL = Moles Of HCl / 1 L = (0.003911822 mol * 1000 ml) / (50 ml * 1 L) = = 0.07823644 Mol/L ~ 0.078 mol/L ******************** How many moles of HCl, in the HCl solution were titrated? .... 0.003912 mol What was the molarity of the HCl solution?.... 0.078 mol/L

This sounds like a gen chem question, so we'll just assume that both HCl and NaOH fully dissociate. First we need to find out how many moles of hydroxide were added (-OH). Make sure all your volumes are in liters. After converting to liters, we find that 0.03722 L of NaOH were added. A molarity multiplied by a volume gives you moles. (0.03722 L NaOH)(0.1051 mol/L NaOH)=0.003911822 moles NaOH added to reach the endpoint. There is only one hydroxide molecule in one molecule of NaOH (NaOH is ionic doesn't really exist as a molecule, but for the purpose of understanding this problem we'll just pretend like it does). So if you added one mole of NaOH to the solution, you added one mole of -OH. Sodium (Na+) is a spectator ion, and is only present for the purposes of balancing charge. Chloride ion (Cl-) is also a spectator ion, all we're concerned about is the H+ and the -OH. HCl and NaOH are a strong acid and a strong base, respectively, and as such they react to form a salt and water. H+ and -OH react one to one, and since you've titrated until the endpoint was reached, you can say that the moles -OH and H+ are equal. In reality, the equivalence point is the point of titration at which the moles -OH equal the moles H+, but for this problem it's irrelevant. So the moles H+ (and by extension the moles HCl) are also 0.003911822 moles. The molarity of the HCl is then 0.003911822 moles/0.050L=0.07823M