Calculate the molar heat of vaporization of a substance given that 0.440 mol of the substance absorbs 23.9 k?
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Answer:
0.440mol * 23.9 kJ =10.5kJ/mol
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Other answers
? kJ/mol = 23.9 kJ/o.440 mole = 54.3 kJ/mol
0.440mol * 23.9 kJ =10.5kJ/mol
beatka
? kJ/mol = 23.9 kJ/o.440 mole = 54.3 kJ/mol
Halchemist
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