What Volume in liters of oxygen at STP is released by heating 13.14 g of HgO?
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Answer:
1) find the molar mass of HgO 2) find the amount of moles of HgO in 13.14g: (13.14g)/(molar mass of HgO) 3) Since 2 moles of HgO would completely react to form one mole of O2, you have this many moles of O2 formed: n = (6.57 g)/(molar mass of HgO). 4) Calculate the required volume of O2 at STP by the ideal gas law: PV = nRT. or: V = nRT/P OK?
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1) find the molar mass of HgO 2) find the amount of moles of HgO in 13.14g: (13.14g)/(molar mass of HgO) 3) Since 2 moles of HgO would completely react to form one mole of O2, you have this many moles of O2 formed: n = (6.57 g)/(molar mass of HgO). 4) Calculate the required volume of O2 at STP by the ideal gas law: PV = nRT. or: V = nRT/P OK?
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