In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many liters of hydrogen gas will be produced fro?
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Answer:
the limiting reactant in this reaction is HCl, to get number of moles of HCl, you go .075 x 3 = 0.225 moles HCl since there are two moles of HCl for ever moles of H2, thus 0.225/2 = 0.1125 moles H2 any gas under STP is 22.4 L per mole, thus 0.1125 x 22.4 = 2.52 L H2 so the answer is C
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Sean
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Selena
the limiting reactant in this reaction is HCl, to get number of moles of HCl, you go .075 x 3 = 0.225 moles HCl since there are two moles of HCl for ever moles of H2, thus 0.225/2 = 0.1125 moles H2 any gas under STP is 22.4 L per mole, thus 0.1125 x 22.4 = 2.52 L H2 so the answer is C
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