Find solution
What is the molarity of the solution?

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25?

  • Answer:

    moles = conc x volume 0.355M x 0.0282L= 0.01 moles of H2SO4. Remember sulphuric acid is diprotic so it will release 2 from each molecule. So moles of protons = 0.01 x 2 = 0.02 moles of H+ For neutralization: moles H+ = moles OH- Therefore moles of NaOH = 0.02 conc = moles / volume Conc NaOH = 0.02 / 0.025L = 0.8M Answer is (a)

drems_newarni at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

moles = conc x volume 0.355M x 0.0282L= 0.01 moles of H2SO4. Remember sulphuric acid is diprotic so it will release 2 from each molecule. So moles of protons = 0.01 x 2 = 0.02 moles of H+ For neutralization: moles H+ = moles OH- Therefore moles of NaOH = 0.02 conc = moles / volume Conc NaOH = 0.02 / 0.025L = 0.8M Answer is (a)

Related Q & A:

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.