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Which of the following atom is the most paramagnetic and why?

Which atom has a change in oxidation number of –3 in the following redox reaction?

  • Answer:

    1. It's Cr but you have an incomplete equation. I assume the products are KOH + Cr2(SO4)3. In which case, Cr goes from +6 to +3, a change of -3. 2. Mercury is the most easily reduced, of the metals listed. 3. From a table of standard electrode potentials: Zn2+ + 2 e− Zn(s) −0.7618 Cu2+ + 2 e− Cu(s) +0.340 Zn(s) is the negative electrode (anode) because its reduction potential is lower than that of Cu(s).

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1. It's Cr but you have an incomplete equation. I assume the products are KOH + Cr2(SO4)3. In which case, Cr goes from +6 to +3, a change of -3. 2. Mercury is the most easily reduced, of the metals listed. 3. From a table of standard electrode potentials: Zn2+ + 2 e− Zn(s) −0.7618 Cu2+ + 2 e− Cu(s) +0.340 Zn(s) is the negative electrode (anode) because its reduction potential is lower than that of Cu(s).

David

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