Precipitation Stoichiometry Problems?
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Hey there! I have 2 problems that I can't seem to get. Any help would be greatly appreciated! 1. Co2(SO4)3(aq) + 3Ca(OH)2(aq) 2Co(OH)3(s) + 3CaSO4(aq) What volume in mL of 0.2500 M Co2(SO4)3 is required to react completely with (a) 25.00 mL of 0.0315 M Ca(OH)2 (b) 5.00 g of Ca(OH)2 2. 2Na3PO4(aq) + 3CaCl2(aq) Ca3(PO4)2(s) + 6NaCl(aq) How many grams of Ca3(PO4)2 are obtained when 15.00 mL of 0.1386 M Na3PO4 are mixed with 20.00 mL of 0.2118 M CaCl2? Thanks so much!
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Answer:
1) a) 25ml (0.0315M) = 0.7875 mmol x (1/3) x (1/0.25M) = 1.05 ml b) 5g x (1mol/74.09g) x (1/3) x (1/0.25M) = 0.08998 ml 2) determine limiting reactant, 15 ml (0.1386M) = 2.079 mmol x (3/2) = 3.1185 mmol needed of CaCl2 20 ml (0.2118M) = 4.236 mmol available use Na3PO4 as basis, 2.079 x 0.5 x (310.1782g/mol) x (1mol/1000mmol) = 0.322 g
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Other answers
1) a) 25ml (0.0315M) = 0.7875 mmol x (1/3) x (1/0.25M) = 1.05 ml b) 5g x (1mol/74.09g) x (1/3) x (1/0.25M) = 0.08998 ml 2) determine limiting reactant, 15 ml (0.1386M) = 2.079 mmol x (3/2) = 3.1185 mmol needed of CaCl2 20 ml (0.2118M) = 4.236 mmol available use Na3PO4 as basis, 2.079 x 0.5 x (310.1782g/mol) x (1mol/1000mmol) = 0.322 g
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