Initial rate question?

Chemistry Rate of Law Question?

  • Hey guys, My question is how do you determine the rate law exponent of a reactant (when there are more than one reactant), through the initial rates method if the concentration of that reactant differs in each trial and does not have the same concentration value as any other trial. For Example assume the rate law expression is A + 2B = C + 2D. What is the rate law expression for this reaction? Expt {A} mol/L {B} mol/L Initial Rate of Formation of C (M/min) 1 .10 .10 2.0 x 10^-4 2 .30 .30 6.0 x 10^-4 3 . 30 .10 2.0 x 10^-4 4 .40 .20 4.0 x 10^-4 If anyone would take the time to solve this problem for me, I would greatly appreciate it

  • Answer:

    comparing 1. and 3. reaction is independent of reactant A comparing 3. and 2. it shows that it is a first order reaction therefore rate = k[B]

Lee R at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

comparing 1. and 3. reaction is independent of reactant A comparing 3. and 2. it shows that it is a first order reaction therefore rate = k[B]

SinZw

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.