Chemistry Rate of Law Question?
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Hey guys, My question is how do you determine the rate law exponent of a reactant (when there are more than one reactant), through the initial rates method if the concentration of that reactant differs in each trial and does not have the same concentration value as any other trial. For Example assume the rate law expression is A + 2B = C + 2D. What is the rate law expression for this reaction? Expt {A} mol/L {B} mol/L Initial Rate of Formation of C (M/min) 1 .10 .10 2.0 x 10^-4 2 .30 .30 6.0 x 10^-4 3 . 30 .10 2.0 x 10^-4 4 .40 .20 4.0 x 10^-4 If anyone would take the time to solve this problem for me, I would greatly appreciate it
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Answer:
comparing 1. and 3. reaction is independent of reactant A comparing 3. and 2. it shows that it is a first order reaction therefore rate = k[B]
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Other answers
comparing 1. and 3. reaction is independent of reactant A comparing 3. and 2. it shows that it is a first order reaction therefore rate = k[B]
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