A 2.30m solution of urea (CO(NH2)2;FW=60.0) in water has a density of 1.14g/mL. Calculate the mass percent of?
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Answer:
This means that 1L of a solution contains 2.3*60g/mol = 138g of urea. A mass of 1L is 1.14g/mL*1000mL = 1140g. Then the mass percent is 138g*100%/1140g = 12.1%
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Other answers
This means that 1L of a solution contains 2.3*60g/mol = 138g of urea. A mass of 1L is 1.14g/mL*1000mL = 1140g. Then the mass percent is 138g*100%/1140g = 12.1%
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