Combined Gas Law problems?10 POINTS!CHEMISTRY!?
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Answer:
PROBLEM ONE P1V1/ T1 = P2V2/T2 So 806 cm3 = .806 L and 26.3 oC= 299.3 K and 103.0 kPa = 1.017 atm (1.017)(.806)/(299.3) = (1)(v2)/(273) 0.819702/ 299.3 = V2/ 273 223.778646 = 299.3 V2 0.7476733912462412 = V2 Round to get .748L ****Problem 2**** 96 cm^3 = .096L 27oC= 300K 16.1psi= 1.095540015 atm.(round to 1.096) 70 oC = 343K 127 kPa = 127000 Pa = 1.253392549 atm(round to 1.253) P1V2/T1 = P2V2/T2 (1.096)(.096)/ 300 = (1.253)(V2)/ 343 0.105216/300 = 1.253V2 / 343 (Proportion set up) 375.9V2 = 36.089088 (divide) V2 = 0.0960071508379888( round to .096L) Email me if you need me to explain in more detail like the cross multiplying, and etc. [email protected]
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Other answers
PROBLEM ONE P1V1/ T1 = P2V2/T2 So 806 cm3 = .806 L and 26.3 oC= 299.3 K and 103.0 kPa = 1.017 atm (1.017)(.806)/(299.3) = (1)(v2)/(273) 0.819702/ 299.3 = V2/ 273 223.778646 = 299.3 V2 0.7476733912462412 = V2 Round to get .748L ****Problem 2**** 96 cm^3 = .096L 27oC= 300K 16.1psi= 1.095540015 atm.(round to 1.096) 70 oC = 343K 127 kPa = 127000 Pa = 1.253392549 atm(round to 1.253) P1V2/T1 = P2V2/T2 (1.096)(.096)/ 300 = (1.253)(V2)/ 343 0.105216/300 = 1.253V2 / 343 (Proportion set up) 375.9V2 = 36.089088 (divide) V2 = 0.0960071508379888( round to .096L) Email me if you need me to explain in more detail like the cross multiplying, and etc. [email protected]
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