Chemistry help - molar heat of vaporization problem? ill answer yours..?
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Answer:
set up a proportion. molar heat of vaporization = kj absorbed for one mole so.. 27.9kj/.527mol= x/1mol x= 52.94kj
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Other answers
set up a proportion. molar heat of vaporization = kj absorbed for one mole so.. 27.9kj/.527mol= x/1mol x= 52.94kj
KL
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