A 120g glass container with a specific heat capacity of 840J/kgC contains 250g of water at 10'C.?
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Answer:
first remember that units are of prime importance second energy conservation can be used as no loss is specified so heat given by steam raises temp of the system let mass of steam in grams be x dQ= ms dt {for temp change} dQ=ml {for phase change q is heat, m mass, s specific heat,l latent heat and dt change in temp heat reqd for system (water+glas) to be raised to 50' = (250*4.20*(50-40)) + (120*0.84*(50-40)) heat given by steam = heat given by cooling steam+ heat given by liquification+ heat given when the steam which is water nowwhen it cools from 100 to 50 = (x*2.01*(150-100)) + (x*2.26*1000) +(x*4.2*(100-50)) now equate them and solve for x.. hope this helps
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Other answers
first remember that units are of prime importance second energy conservation can be used as no loss is specified so heat given by steam raises temp of the system let mass of steam in grams be x dQ= ms dt {for temp change} dQ=ml {for phase change q is heat, m mass, s specific heat,l latent heat and dt change in temp heat reqd for system (water+glas) to be raised to 50' = (250*4.20*(50-40)) + (120*0.84*(50-40)) heat given by steam = heat given by cooling steam+ heat given by liquification+ heat given when the steam which is water nowwhen it cools from 100 to 50 = (x*2.01*(150-100)) + (x*2.26*1000) +(x*4.2*(100-50)) now equate them and solve for x.. hope this helps
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