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Why is electric demand and kwh not same for 2 electric meter consuming same amount of electricity?

  • Electricity provided by 208v 3 phase Socal Edison. I have 2 meters that feed from same transformer. Meter 1 feeds to main panel A. From panel A subs to sub-panel B. Meter 2 feeds to main panel C From panel C subs to sub-panel D. I tied panel B to D together by put 3 phases breakers in both panels and wire 3 hots to each corresponding breaker, making sure all phases are matched so they can not cause shorts then neutral to neutral and ground to ground (I know it is danger and I have my reason for doing so. Please don't criticize)I turn on power and observe power consumption for both meters. In theory since meter 1 and 2 are tied together, they should consume same amount of power. But in reality each meter consumes individually as the jumping from meter B to D does not exist ( I did make sure the jumping worked and electricity flows freely between meter 1 and 2. I can turn off main breaker of either meter 1 or 2 and still get power for all circuits. eg. main breaker for meter 1 is off so electricity is not being fed from meter 1. All circuits power under meter 1 (panel a and B) still work because power is fed thru meter 2 to panel C then to D then to B then to A) Can anyone explain why it is not working as in theory? Please only reply if you know what you are talking about.

  • Answer:

    1. You should not be doing this. It presents a life safety hazard to anyone who might be called in to work on the system and dependin how you made those conections, might allow a feeder to be overloaded. 2. You have created a net with two metered sources, multiple variable loads, and varying resistances between them. Resistance will change how current flows. It would be odd indeed if those meters both passed the same amount of power. IF YOU DIDN'T KNOW THIS YOU HAVE NO BUSINESS MODIFYING A POWER SYSTEM.

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Other answers

Someone said an earlier question was in the running for the most confusing problem of the month. Yours is too.

Just because you've tied them together doesn't mean the actual demand is equal on each input. Electricity follows the path of least resistance, and that may not be equal on each path. But seriously, you shouldn't be doing this.

1. You should not be doing this. It presents a life safety hazard to anyone who might be called in to work on the system and dependin how you made those conections, might allow a feeder to be overloaded. 2. You have created a net with two metered sources, multiple variable loads, and varying resistances between them. Resistance will change how current flows. It would be odd indeed if those meters both passed the same amount of power. IF YOU DIDN'T KNOW THIS YOU HAVE NO BUSINESS MODIFYING A POWER SYSTEM.

Irv S

Just because you've tied them together doesn't mean the actual demand is equal on each input. Electricity follows the path of least resistance, and that may not be equal on each path. But seriously, you shouldn't be doing this.

Whatevers

Someone said an earlier question was in the running for the most confusing problem of the month. Yours is too.

Rick

Aside from the already admitted stupidity and danger if work is attempted on one of the cross connected panels without getting all the other connections off, I don't see anything in that mess of details that says that there is absolutely no other use of electricity off of the meters by anything else in the building. Nobody is turning on and off the lights in the bathroom or running the copier in the front office. No automatic lighting equipment or sump pump is adding to the load. Any of those would make the two meters different. In fact, unless the feeds to the two meters are bonded just outside the building - which is often the case - there may be differences in the feed voltage to each meter depending on the load of the supply lines from other companies. One may be at 209 volts and the other at 207 or even a greater difference. And what is your load that is taking the wattage? Is it inductive? How does the inductive load interact with the wiring you have done? Are there phase changes surging through the loops and interconnections, affecting other equipment?

I don't trust the Power Company either, but I know they're way smarter than I am. Your service drops are probably 1-0. The subfeeders are probably smaller and of different length. Unless you tied the subpanels with 1-0, your resistance will be different. (and your current draw will differ) There are inductive watt meters that you can attach to your service drop to verify meter accuracy (the power company uses them when they suspect diversion, and yes they are pricey) Your power company will usually test your meters on request if you suspect overcharge. Good Luck PS: Bare in mind that the resistance of 1-0 is 1000 times less than AWG#12. (1-0=.000098ohms/ft. #12=.00158ohms/ft) If you can use Kirchoff's Laws, you would have to measure the exact length of each different wire gauge from each separate source.

Aside from the already admitted stupidity and danger if work is attempted on one of the cross connected panels without getting all the other connections off, I don't see anything in that mess of details that says that there is absolutely no other use of electricity off of the meters by anything else in the building. Nobody is turning on and off the lights in the bathroom or running the copier in the front office. No automatic lighting equipment or sump pump is adding to the load. Any of those would make the two meters different. In fact, unless the feeds to the two meters are bonded just outside the building - which is often the case - there may be differences in the feed voltage to each meter depending on the load of the supply lines from other companies. One may be at 209 volts and the other at 207 or even a greater difference. And what is your load that is taking the wattage? Is it inductive? How does the inductive load interact with the wiring you have done? Are there phase changes surging through the loops and interconnections, affecting other equipment?

Mike1942f

I don't trust the Power Company either, but I know they're way smarter than I am. Your service drops are probably 1-0. The subfeeders are probably smaller and of different length. Unless you tied the subpanels with 1-0, your resistance will be different. (and your current draw will differ) There are inductive watt meters that you can attach to your service drop to verify meter accuracy (the power company uses them when they suspect diversion, and yes they are pricey) Your power company will usually test your meters on request if you suspect overcharge. Good Luck PS: Bare in mind that the resistance of 1-0 is 1000 times less than AWG#12. (1-0=.000098ohms/ft. #12=.00158ohms/ft) If you can use Kirchoff's Laws, you would have to measure the exact length of each different wire gauge from each separate source.

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