Develop a relation to convert this scale to degree Celsius?
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Answer:
That is NOT an absolute scale.... 100X ⟷ 0C 500X ⟷ 100C Assume the formula is of the form of C = aX + b substitute. 0 = 100a + b 100 = 500a + b solve for a and b b = –100a 100 = 500a + (–100a) 400a = 100 a = 1/4 b = –100(1/4) = –25 so the formula is C = (X/4) – 25 ⬅ 4C = X – 100 X = 4C + 100 ⬅ check 100X C = 25–25 = 0 ok 500X C = (500/4) – 25 = 125–25 = 100 ok Note that for C = –273 (0K, absolute zero) X = 4(–273) + 100 = –992 NOT zero, which it should be if this is an absolute scale.
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Other answers
That is NOT an absolute scale.... 100X ⟷ 0C 500X ⟷ 100C Assume the formula is of the form of C = aX + b substitute. 0 = 100a + b 100 = 500a + b solve for a and b b = –100a 100 = 500a + (–100a) 400a = 100 a = 1/4 b = –100(1/4) = –25 so the formula is C = (X/4) – 25 ⬅ 4C = X – 100 X = 4C + 100 ⬅ check 100X C = 25–25 = 0 ok 500X C = (500/4) – 25 = 125–25 = 100 ok Note that for C = –273 (0K, absolute zero) X = 4(–273) + 100 = –992 NOT zero, which it should be if this is an absolute scale.
billruss...
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