This is an easy physics question, but I just can't get the right answer. Please solve it.?
-
-
Answer:
You're being asked for the centripetal acceleration v^2/r r is the radius of the orbit. You are given that, but you should convert to meters. v is the speed of the moon in its orbit. To find that, divide the total distance it travels in one circumference (2*pi*r, expressed in meters) by the time it takes to travel that distance (27.3 days, expressed in seconds). There are 24 * 3600 = 86400 seconds in a day
ionn at Yahoo! Answers Visit the source
Other answers
You're being asked for the centripetal acceleration v^2/r r is the radius of the orbit. You are given that, but you should convert to meters. v is the speed of the moon in its orbit. To find that, divide the total distance it travels in one circumference (2*pi*r, expressed in meters) by the time it takes to travel that distance (27.3 days, expressed in seconds). There are 24 * 3600 = 86400 seconds in a day
Randy P
Related Q & A:
- How come I can't get into the chat rooms?Best solution by answers.help.ea.com
- How come i can't get on yahoo messenger?? have downloaded and removed several times?Best solution by Yahoo! Answers
- Why i can't get into my email?Best solution by Yahoo! Answers
- I can't get into a yahoo chatroom.Best solution by Yahoo! Answers
- What is a post car ? I see that on a muscle car ad and I just don't get it?Best solution by Yahoo! Answers
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.