A mass of .470kg is suspended from a spring with a constant of 56.2n/m find the equilibrium position?
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Answer:
as u must know:total force on the mass in equilibrium position is 0 =>W- Fe=0 =>mg=ky ("k" is the constant,"y" is the amount the spring is stretched to reach the equilibrium position,Fe=ky the spring,s force on the mass)
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as u must know:total force on the mass in equilibrium position is 0 =>W- Fe=0 =>mg=ky ("k" is the constant,"y" is the amount the spring is stretched to reach the equilibrium position,Fe=ky the spring,s force on the mass)
Fatema
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