What force does the water exert on the man?
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Answer:
The braking force F = mV/dT = 92*sqrt(2*9.81*3.2)/.5 = ? N You can do the math. The physics is this. The man m = 92 kg enters the water at V = sqrt(2gh) where h = 3.2 meters from the board. g = 9.81 m/sec^2. The impact interval is dT = .5 sec to stop him from the speed V. The F relationship derives from the definition of impulse dP = d(mV) = m dV = mV = F dT. Where dV = 0 - (-V) = V is the change in velocity upon entering the water.
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Other answers
The braking force F = mV/dT = 92*sqrt(2*9.81*3.2)/.5 = ? N You can do the math. The physics is this. The man m = 92 kg enters the water at V = sqrt(2gh) where h = 3.2 meters from the board. g = 9.81 m/sec^2. The impact interval is dT = .5 sec to stop him from the speed V. The F relationship derives from the definition of impulse dP = d(mV) = m dV = mV = F dT. Where dV = 0 - (-V) = V is the change in velocity upon entering the water.
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