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Can you please answer this physics question?

PLEASE ANSWER PHYSICS QUESTION?

  • Answer:

    You need to subtract the force against the boat from the force moving the boat foward to get the net force. 2.56 x 10^3 N - 1.89 x 10^3 N = .67 x 10^3N forward = 670N F=ma 670N = 1311.8 (a) a= .511m/s^2

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You need to subtract the force against the boat from the force moving the boat foward to get the net force. 2.56 x 10^3 N - 1.89 x 10^3 N = .67 x 10^3N forward = 670N F=ma 670N = 1311.8 (a) a= .511m/s^2

Brodo

Seems simple. so total forces has to equal m*a. You need a. 2.56 x 10^3 N + -(1.89 x 10^3 N) = (1311.8kg)*a solve for a = 670N / 1311.8kg a = about 0.511 m/s^2 or in same form: 5.11 x 10^-1 m/s^2

Ganja-Man-

net force = m a net force = forward pushing force - frictio = 2560N - 1890N = 670N 670N = 1311.8kg x a a= 0.511m/s/s

kuiperbelt2003

Seems simple. so total forces has to equal m*a. You need a. 2.56 x 10^3 N + -(1.89 x 10^3 N) = (1311.8kg)*a solve for a = 670N / 1311.8kg a = about 0.511 m/s^2 or in same form: 5.11 x 10^-1 m/s^2

Ganja-Man-

net force = m a net force = forward pushing force - frictio = 2560N - 1890N = 670N 670N = 1311.8kg x a a= 0.511m/s/s

kuiperbelt2003

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