A boy coasts down a hill on a sled, reaching a level surface at the bottom with a speed of 6.8 m/s. If the coe?
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Answer:
Frictional Force = 0.050 x 580 = 29 N Kinetic Energy = 0.5 x m x v^2 = 0.5 x (580/9.8) x 6.8^2 = 1368.3 J Distance = Work Done / Force = 1368.3/29 = 47.2 m
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Other answers
Frictional Force = 0.050 x 580 = 29 N Kinetic Energy = 0.5 x m x v^2 = 0.5 x (580/9.8) x 6.8^2 = 1368.3 J Distance = Work Done / Force = 1368.3/29 = 47.2 m
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