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Find an equation of the plane through the point and perpendicular to the given line?

Find an equation of the plane passing through the point perpendicular to the given vector or line?

  • Answer:

    first you want the normal to the plane the vector that is perpendicular is the NORMAL VECTOR a(x - x1) + b(y - y1) + c(z - z1) = 0 is the equation of a plane that is normal to the vector (a,b,c) and passes through the point (x1,x2,x3) since I cant tell what the given vector is from your question I will let you do the math that is the answer all you have to do is plug in the values another form of the answer is ax + by + cz = a*x1 + b*y1 + c*z1 ax + by + cz = d where d = a*x1 + b*y1 + c*z1 again the vector perpendicular to the plane is (a,b,c) or ai + bi + ci and the point on the plane is (x1,y1,z1) hope that helps

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first you want the normal to the plane the vector that is perpendicular is the NORMAL VECTOR a(x - x1) + b(y - y1) + c(z - z1) = 0 is the equation of a plane that is normal to the vector (a,b,c) and passes through the point (x1,x2,x3) since I cant tell what the given vector is from your question I will let you do the math that is the answer all you have to do is plug in the values another form of the answer is ax + by + cz = a*x1 + b*y1 + c*z1 ax + by + cz = d where d = a*x1 + b*y1 + c*z1 again the vector perpendicular to the plane is (a,b,c) or ai + bi + ci and the point on the plane is (x1,y1,z1) hope that helps

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