I don't understand this physics?
-
I have found a contradiction in my physics, and I need help understanding why I made this mistake. (For simplicity purposes I will only state the part of the question I have trouble with, not the entire question). Question 1 is: A block with a mass m starts falling down a slope that is banked at theta degrees. What is the normal force of the block ? My solution: mass*gravity*sin(theta). This appears correct. Furthermore, assuming no coefficient of friction, the frictional force is mass*gravity*cos(theta). The next question's solution appears to be the exact opposite Question 2: A car with mass m is on a banked highway curve (ie. the road is not flat) of theta degrees. What is the normal force of the car? My solution: n*cos(theta) = mg n = mg/cos(theta) This is also correct.. So how come the normal force is sin for the first question, but cos for the second question
-
Answer:
Question 1. normal force of the block on the sloping path = mg cos theta, whether frictions acts or does not act. The cause for this force is earths pull on the block. mg sin theta is the earth's pull on the block tangential to the surface of the slope in which direction it is free to move. Same argument works for the car at rest on the banked road, for the normal force by the car on the road. only difference is that on a banked road, the car travels on a circular path in the horizontal plane. Now the force due to earth cannot have any component in a direction perpendicular to the vertical force. But the reaction, N (which is adjustable, it need not be always mg cos theta) of the road can have. N cos theta is the force which provides centripetal force to the car to move in a circle. but that is altogether a different consideration.
Tam at Yahoo! Answers Visit the source
Other answers
Question 1. normal force of the block on the sloping path = mg cos theta, whether frictions acts or does not act. The cause for this force is earths pull on the block. mg sin theta is the earth's pull on the block tangential to the surface of the slope in which direction it is free to move. Same argument works for the car at rest on the banked road, for the normal force by the car on the road. only difference is that on a banked road, the car travels on a circular path in the horizontal plane. Now the force due to earth cannot have any component in a direction perpendicular to the vertical force. But the reaction, N (which is adjustable, it need not be always mg cos theta) of the road can have. N cos theta is the force which provides centripetal force to the car to move in a circle. but that is altogether a different consideration.
Let'slea...
Related Q & A:
- How can you erase a link on the tab that I don't want to have anymore?Best solution by Yahoo! Answers
- Is there any way I can get my MSN password back if I don't know the secret question that it asks?Best solution by Yahoo! Answers
- How should I deal with people I don't like at work?Best solution by time.com
- How do I find a certain tv channel if I don't know what number it is?Best solution by timewarnercable.com
- Should I apply for a job if I don't have the minimum requirements?Best solution by themuse.com
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.