What links a click/tap position to select an object on screen?

Select which statement where work is done on an object.?

  • A.)the perpendicular component of the force time the displacement of the object. B.)the parallel component of the force times the displacement of the object. C.)the perpendicular component of the force times the displacement of the object. D.)the parallel component of the force times the displacement of the object where the object moves along a path that returns the object to its starting position. ?

  • Answer:

    work done is the dot product of force times displacement. Hence if the displacement and force are perpendicular then value of work will be zero..similarly in your last option value of work is zero because displacement is zero in such a case..hence your option B will be correct

Kevin B at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

work done is the dot product of force times displacement. Hence if the displacement and force are perpendicular then value of work will be zero..similarly in your last option value of work is zero because displacement is zero in such a case..hence your option B will be correct

hamzapal...

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.