An 900-kg (1989 lb) dragster, starting from rest, attains a speed of 26.9 m/s (60.3 mph) in 0.59 s.?
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An 900-kg (1989 lb) dragster, starting from rest, attains a speed of 26.9 m/s (60.3 mph) in 0.59 s. (a) Find the average acceleration of the dragster during this time interval. m/s2 (b) What is the magnitude of the average net force on the dragster during this time? N (c) Assume that the driver has a mass of 68 kg. What horizontal force does the seat exert on the driver? N
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Answer:
You should complain to your teacher how unrealistic this problem is. The acceleration is too fast even for a dragster. Even as the previous person said, you would need rockets attached to attain that type of force in such a short amount of time. Tires alone would not be able to withstand all that.
Emily at Yahoo! Answers Visit the source
Other answers
a) Acceleration = (v/t), = 26.9/0.59, = 45.59m/sec^2. b) Force = (ma), = 900 x 45.59, = 41,031N. c) Force = (68 x 45.9) = 3,121.2N.
Technobuff
a) Acceleration = (v/t), = 26.9/0.59, = 45.59m/sec^2. b) Force = (ma), = 900 x 45.59, = 41,031N. c) Force = (68 x 45.9) = 3,121.2N.
Technobuff
You should complain to your teacher how unrealistic this problem is. The acceleration is too fast even for a dragster. Even as the previous person said, you would need rockets attached to attain that type of force in such a short amount of time. Tires alone would not be able to withstand all that.
SoCalGuy
almost 50/msec^2 NOT gonna happen 1 g weight is 9.8 M/S^2 FIVE g on wheels, not without a rocket booster
Richard B
almost 50/msec^2 NOT gonna happen 1 g weight is 9.8 M/S^2 FIVE g on wheels, not without a rocket booster
Richard B
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