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What is the magnitude of the third force?

Physics: What is the magnitude and direction of a third force?

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    this question can be solved by resolution of vectors we need to find the resultant of the two forces and than the third force will be opposite in direction and equal in magnitude to the resultant. x components F1x=0(at 90') F2x=44cos60=22 y components F1y=33sin90= 33N F2y=44sin60=38.10 Rx=22N Ry=33+38.1=71 R^2=(Rx)^2+(Ry)^2 R=72N angle will be tan(inverse)Ry/Rx Q=72.7 the angle should be in the 3rd quardrant and will be 252

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this question can be solved by resolution of vectors we need to find the resultant of the two forces and than the third force will be opposite in direction and equal in magnitude to the resultant. x components F1x=0(at 90') F2x=44cos60=22 y components F1y=33sin90= 33N F2y=44sin60=38.10 Rx=22N Ry=33+38.1=71 R^2=(Rx)^2+(Ry)^2 R=72N angle will be tan(inverse)Ry/Rx Q=72.7 the angle should be in the 3rd quardrant and will be 252

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