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How far is HOLY HILL from PORTAGE?

How far from the base of the hill does he end up?

  • Josh starts his sled at the top of a 3.3 -high hill that has a constant slope of 25 . After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.08. I need to know how far from the base of the hill he will end up.

  • Answer:

    By the law of energy conservation:- =>KE(bottom) = PE(top) =>KE(bottom) = mgh =>KE(bottom) = m x 9.8 x 3.3 =>KE(bottom) = 32.34m Jule By work energy theorem:- =>W(friction) = ∆KE =>F(friction) x s = 32.34m =>µk x mg x s = 32.34m =>s = 32.34/[µk x g] =>s = 32.34/[0.08 x 9.8] =>s = 41.25 m

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By the law of energy conservation:- =>KE(bottom) = PE(top) =>KE(bottom) = mgh =>KE(bottom) = m x 9.8 x 3.3 =>KE(bottom) = 32.34m Jule By work energy theorem:- =>W(friction) = ∆KE =>F(friction) x s = 32.34m =>µk x mg x s = 32.34m =>s = 32.34/[µk x g] =>s = 32.34/[0.08 x 9.8] =>s = 41.25 m

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