Calculate velocity of electron with a given work function?
-
The work function for platinum is 6.35 eV. Calculate the velocity of an electron ejected by a photon that has a wavelength that is half the wavelength required to emit electrons from the surface. I'm not sure how to calculate the velocity if I'm not given the frequency or wavelength. The only way I've tried to solve this problem is making 6.35 eV = 1/2mv^2. My result was v=1.49x10^ -25. My instructor says there is a math error but I have no clue where to go from here. Any suggestions are appreciated.
-
Answer:
First you have to convert the eV to joules and than you use E=mv^2/2 the mass of electron m=9.1X10^ -31 kg
crys2982 at Yahoo! Answers Visit the source
Other answers
First you have to convert the eV to joules and than you use E=mv^2/2 the mass of electron m=9.1X10^ -31 kg
DrNeedle
Related Q & A:
- How to calculate max/min scales on a scatter plot?Best solution by Cross Validated
- How to pass multiple parameters in a single Ajax function?Best solution by stackoverflow.com
- Can I automatically send out an email on a given date?Best solution by Yahoo! Answers
- How does a headset on a bike work?Best solution by slowtwitch.com
- How do you calculate the molar mass of a compound?Best solution by eHow old
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.