Find solution
Is it legal to own a submarine on a lake?

An air bubble has a volume of 1.45 cm^3 when it is released by a submarine 105 m below the surface of a lake.?

  • I am getting 148.74cm. But the website I have to submit my answers is telling me that I am wrong. Though, I don't know what I am doing wrong. Someone help? This is what I am doing: P2=P1 + density(g)(m) = (1.013x10^5)+(10^3)(9.8)(105) =10391300Pa V1=P2V2/P1 =[(10391300Pa)(1.45cm^3)]/(1.013x10^5) =148.74cm. But it's telling me that I am wrong.

  • Answer:

    An air bubble has a volume of 1.45 cm^3 when it is released by a submarine 105 m below the surface of a lake. What is the volume of the bubble when it reaches the surface? Assume the temperature and the number of air molecules in the bubble remain constant during its ascent. The net force on the air bubble is the buoyant force – the weight of the air bubble The buoyant force = the weight of volume of the displaced water. Volume of displaced water = volume of air bubble Initial volume of air bubble = 1.45 cm^3 As the air bubble rises to the surface the water pressure decreases, so the volume of the air bubble increases. To determine the actual volume increase, we need the total pressure = atmosphere pressure + water pressure. Standard atmospheric pressure = 101,325 Pa = 101,325 N/m^2 The water pressure = Density * depth * g Density of water = 1000 kg/m^3 Water pressure = 1000 * 105 * 9.8 = 1.029 * 10^6 N/m^2 Total pressure = 101,325 + 1.029 * 10^6 Pressure at surface = 101,325 Volume at surface = volume at 105 m under surface * 101,325/(101,325 + 1.029 * 10^6) Volume at surface = 1.45 * (101,325 + 1.029 * 10^6)/ 101,325 Volume at surface = 16.175 cm^3

Kiwi - at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

An air bubble has a volume of 1.45 cm^3 when it is released by a submarine 105 m below the surface of a lake. What is the volume of the bubble when it reaches the surface? Assume the temperature and the number of air molecules in the bubble remain constant during its ascent. The net force on the air bubble is the buoyant force – the weight of the air bubble The buoyant force = the weight of volume of the displaced water. Volume of displaced water = volume of air bubble Initial volume of air bubble = 1.45 cm^3 As the air bubble rises to the surface the water pressure decreases, so the volume of the air bubble increases. To determine the actual volume increase, we need the total pressure = atmosphere pressure + water pressure. Standard atmospheric pressure = 101,325 Pa = 101,325 N/m^2 The water pressure = Density * depth * g Density of water = 1000 kg/m^3 Water pressure = 1000 * 105 * 9.8 = 1.029 * 10^6 N/m^2 Total pressure = 101,325 + 1.029 * 10^6 Pressure at surface = 101,325 Volume at surface = volume at 105 m under surface * 101,325/(101,325 + 1.029 * 10^6) Volume at surface = 1.45 * (101,325 + 1.029 * 10^6)/ 101,325 Volume at surface = 16.175 cm^3

electron...

Electron 1 has already given the correct answer I shall try to pint out your mistake. P2=P1 + density(g)(m) = (1.013x10^5)+(10^3)(9.8)(105) = 101300 + 1029000 = 1130300 V1=P2V2/P1 =[(1130300Pa)(1.45cm^3)]/(1.013x10^5) =16.18 cm^3

Let'slearntothink

Electron 1 has already given the correct answer I shall try to pint out your mistake. P2=P1 + density(g)(m) = (1.013x10^5)+(10^3)(9.8)(105) = 101300 + 1029000 = 1130300 V1=P2V2/P1 =[(1130300Pa)(1.45cm^3)]/(1.013x10^5) =16.18 cm^3

Let'slearntothink

Related Q & A:

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.