Swimming pool water?

A swimming pool of depth 2.2 m is filled with ordinary (pure) water (ρ = 1000 kg/m3).?

• A swimming pool of depth 2.2 m is filled with ordinary (pure) water (ρ = 1000 kg/m3). (a) What is the pressure at the bottom of the pool? answer is to be in pascals b) When the pool is filled with salt water, the pressure changes by 5.6 103 Pa. What is the difference between the density of the salt water and the density of pure water? answer is to be in kg/m^3

• Answer:

  (a) (1000*2.2*9.8) + Atmospheric Pressure (101000 or whatever the number you're suppose to use) (b) Pressure at the bottom of the pool + 5.6 103 Pa (or whatever that number is suppose to be) Combined pressures = Atmospheric Pressure + (2.2*9.8*New Density) Combined pressures - Atmospheric Pressure = (2.2*9.8)*New Density Combined pressures - Atmospheric Pressure = (21.56)*New Density (Combined pressures - Atmospheric Pressure) / 21.56 = New Density New Density - 1000 = The difference between the density of the salt water and the density of pure water I hope that made some kind of sense...