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How much heat is necessary to change 510. g of ice at -10°C to water at 20°C?

  • Answer:

    There's a change of 30C, for a single gram of water that would take 30 calories. You have 510g of water, this means that the total heat needed is 30 x 510 which equals 15300 calories or 15.3kcal.

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There's a change of 30C, for a single gram of water that would take 30 calories. You have 510g of water, this means that the total heat needed is 30 x 510 which equals 15300 calories or 15.3kcal.

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