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How do I calculate the angle of incidence?

I have a doubt regarding lateral displacement being directly proportional to angle of incidence in glass slab?

  • See, when we increase the angle of incidence then angle of emergence should also increase(as we know that angle of incidence=angle of emergence) ,then how can lateral displacement increase ?because if angle of emergence increases then the dis. b/w new original path of the incident ray and emergent ray should remain the same ,i.e. lateral shift should remain the same . Explain.

  • Answer:

    Suppose that your assumption is correct. Now think of a ray incident normally to the slab. Angle of incidence is zero. Angle of emergence is also zero. And you know now the lateral displacement is zero in this case. If your assumption is true, then the lateral displacement should be zero for any angle of incidence. But you know this is not true. ------------------------------ Now think of the other extreme case. The angle of incidence is little less than 90 ° (say 89°) The incident ray is almost parallel to one side of the slab. The emergent ray also is almost parallel to the other side. (Angle of incidence = angle of emergence) Lateral displacement is the thickness of the slab. ------------------------------------ Thus it is seen that the lateral displacement increases from zero to the maximum value , the thickness of the slab. =============================

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Lateral displacement is something related to refraction and not reflection. And in case of refraction it is not "angle of incidence=angle of emergence" It depends on refractive index of the material

My Id

Suppose that your assumption is correct. Now think of a ray incident normally to the slab. Angle of incidence is zero. Angle of emergence is also zero. And you know now the lateral displacement is zero in this case. If your assumption is true, then the lateral displacement should be zero for any angle of incidence. But you know this is not true. ------------------------------ Now think of the other extreme case. The angle of incidence is little less than 90 ° (say 89°) The incident ray is almost parallel to one side of the slab. The emergent ray also is almost parallel to the other side. (Angle of incidence = angle of emergence) Lateral displacement is the thickness of the slab. ------------------------------------ Thus it is seen that the lateral displacement increases from zero to the maximum value , the thickness of the slab. =============================

Pearlsaw...

You are correct. Lateral displacement is certainly NOT related, directly or otherwise, to the angle of incidence. Assuming that we are talking about just one slab, so that thickness and refractive index remain the same, the displacement is related to the SINE of the angle of incidence. A very different matter.

ignoramus

Lateral displacement is something related to refraction and not reflection. And in case of refraction it is not "angle of incidence=angle of emergence" It depends on refractive index of the material

My Id

Idk but I need 3 points before I can vote soooo Answering this gives me 2...

mary

Umm...Some of you guys are wrong! Lateral displacement IS DIRECTLY PROPORTIONAL to the angle of incidence. Lateral displacement is given by the formula d=t*[sin(i-r)/cos(r)] If you put the values in and calculate you tell that lateral displacement is direct propotional to angle of incidence and thickness of glass slab. Cheers!

Ajay

You are correct. Lateral displacement is certainly NOT related, directly or otherwise, to the angle of incidence. Assuming that we are talking about just one slab, so that thickness and refractive index remain the same, the displacement is related to the SINE of the angle of incidence. A very different matter.

ignoramus

For the best answers, search on this site https://shorturl.im/axyaM Lateral displacement increases with increase in angle of incidence..... If t is the thickness of the glass slab. Lateral displacement d = t * {sin (i-r) / cos r} where i is the angle of incidence and r is the angle of refraction. i and r related by the refractive index μ = sini/sin r

Bonnie

Idk but I need 3 points before I can vote soooo Answering this gives me 2...

mary

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