What is the average force of friction on the box?
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Answer:
The average acceleration is [v(5) - v(0)] / (5 - 0) = (0 - 15)/5 = -3 The negative sign indicates that the force opposed the motion. Therefore, the average force over this time interval was (2kg)(3m/s²) = 6N
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Other answers
The average acceleration is [v(5) - v(0)] / (5 - 0) = (0 - 15)/5 = -3 The negative sign indicates that the force opposed the motion. Therefore, the average force over this time interval was (2kg)(3m/s²) = 6N
Ron W
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