Determine the work done by the force of gravity in the process. Answer in units of?
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Answer:
Force = Mass x Gravity ; Work = Force * Displacement. In the Y direction; The force is: 5kg*9.81m/s = 49.05N (this force must be exceeded to lift the block) Y Displacement W value: 49.05N*1.1m = 53.95 N/m X Displacement W value: 49.05N*5.2m= 255N/m Total work done by gravity is 255+53.95 = 308.95 Joules
Tom at Yahoo! Answers Visit the source
Other answers
Indeed W = 9.81(5)(1.1) J. J stands for Joules, which itself has units of kg*m²/s².
Arbitrarily0
Force = Mass x Gravity ; Work = Force * Displacement. In the Y direction; The force is: 5kg*9.81m/s = 49.05N (this force must be exceeded to lift the block) Y Displacement W value: 49.05N*1.1m = 53.95 N/m X Displacement W value: 49.05N*5.2m= 255N/m Total work done by gravity is 255+53.95 = 308.95 Joules
Tom
w=fdcos(theta) so the only time work is done is when the block is being lifted up. which is w=9.81(5)(1.1) the rest of the time the force and displacement have angle 90 between them so work is 0.
Paulie Walnuts
(5 x 9.8) x 5.2m = 254.8 joules.
Technobuff
w=fdcos(theta) so the only time work is done is when the block is being lifted up. which is w=9.81(5)(1.1) the rest of the time the force and displacement have angle 90 between them so work is 0.
Paulie Walnuts
Indeed W = 9.81(5)(1.1) J. J stands for Joules, which itself has units of kg*m²/s².
Arbitrarily0
(5 x 9.8) x 5.2m = 254.8 joules.
Technobuff
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