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Calculating the angular acceleration.

Calculating acceleration?

  • I did a physics experiment in school and need to calculate the acceleration of a trolley. However, i only have the distance the trolley traveled and the time it took it to travel. How can i use this data to figure out the acceleration? Example data: Distance traveled= 0.5 meters Time it took to travel distance= 1.54 seconds Acceleration= ?

  • Answer:

    s = 0.5 * a * t^2 with s = distance (space) a = acceleration t = time 0.5 = 0.5 * a * 1.54^2 a = 0.4 m/s^2

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Pretty simple. :) Just take the distance traveld divided by the time it took to travel the distance. youl get a long number like .32 something something blah blah.which isnt propper but that it breaks it down into milimeters and miliseconds and then just work up.

Donald

s = 0.5 * a * t^2 with s = distance (space) a = acceleration t = time 0.5 = 0.5 * a * 1.54^2 a = 0.4 m/s^2

Steven

Term of accelerations is changing speed1(V1) at time1(t1) subtracted by speed2Vv2) at time2(t2) divided by time2-time1 . To get acceleration you should collect data of what speed of the trolley after distance(V2) 0.5 meter or time (t2)1.54 second. Let me give you an example: V2(speed after travel 0.5m) = 2 m/s. a = (V1-V2)/(t2-t1) = (2-0)/(1.54-0) = 1.3 m/s2. IYou may change it to decceleartion if you select v1 = 2 m/s and V1=0. good luck

Entang S

Hi Emma, Supposing the trolley to have started from rest,we must use Newton's second equation of motion: S=ut+1/2*at^2 u=0(because trolley started from rest and initial velocity is 0) S=0.5 m t=1.54 s 0.5=1/2*a*(1.54)^2 a=(0.5*2)/1.54^2 =0.42165 m/s^2 Thank you for your patience.Good luck.

Sachu

a=(v-v(knot))/t You know v knot =0 You can calculate v from dist/time

Steven Ham

Hi Emma, Supposing the trolley to have started from rest,we must use Newton's second equation of motion: S=ut+1/2*at^2 u=0(because trolley started from rest and initial velocity is 0) S=0.5 m t=1.54 s 0.5=1/2*a*(1.54)^2 a=(0.5*2)/1.54^2 =0.42165 m/s^2 Thank you for your patience.Good luck.

Sachu

Term of accelerations is changing speed1(V1) at time1(t1) subtracted by speed2Vv2) at time2(t2) divided by time2-time1 . To get acceleration you should collect data of what speed of the trolley after distance(V2) 0.5 meter or time (t2)1.54 second. Let me give you an example: V2(speed after travel 0.5m) = 2 m/s. a = (V1-V2)/(t2-t1) = (2-0)/(1.54-0) = 1.3 m/s2. IYou may change it to decceleartion if you select v1 = 2 m/s and V1=0. good luck

Entang S

Pretty simple. :) Just take the distance traveld divided by the time it took to travel the distance. youl get a long number like .32 something something blah blah.which isnt propper but that it breaks it down into milimeters and miliseconds and then just work up.

Donald

a=(v-v(knot))/t You know v knot =0 You can calculate v from dist/time

Steven Ham

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