Domain function help?

Help with domain of a function?

  • Answer:

    The number inside the square root needs to be >= 0 since you cannot take the square root of a negative number. Furthermore, the denominator cannot be zero because you cannot divide by zero. This means that the number inside the square root must not equal zero. Thus, you have (5-x)*(17+x) > 0, which means 5- x > 0 and 17 + x > 0, or 5-x < 0 and 17+ x < 0. So, -17 < x < 5 will work. The other choice (x > 5 and x < -17) cannot be satisifed by any x. So the domain is (-17,5)

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The number inside the square root needs to be >= 0 since you cannot take the square root of a negative number. Furthermore, the denominator cannot be zero because you cannot divide by zero. This means that the number inside the square root must not equal zero. Thus, you have (5-x)*(17+x) > 0, which means 5- x > 0 and 17 + x > 0, or 5-x < 0 and 17+ x < 0. So, -17 < x < 5 will work. The other choice (x > 5 and x < -17) cannot be satisifed by any x. So the domain is (-17,5)

Justin

Put the equation into a graphing calculator and then you can see all possible x-values that the function is at.

LiveLoveLaugh

Nope, the domain is not all real numbers. Substitute number by number to find the domain. {x≤4}

Nope, the domain is not all real numbers. Substitute number by number to find the domain. {x≤4}

Put the equation into a graphing calculator and then you can see all possible x-values that the function is at.

LiveLoveLaugh

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