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How To Solve Simple Bilinear Equations Under Extra Linear Constraints?

How do you solve system of equations? Im not asking you to solve anything for me, just tell me how plz?

  • we are having an algebra test and if i don't pass it i cant get my diploma. i could take it next year or the year after that but i wanna get it over with now. so one of the things we have to do is solve system of equations but i don't remember how to do it. i thought if you had one that was like 3y=2x= 3 and the other problem would be like 3xx=y so you solve for x by replacing all of the ys in the first equation with 3xx and do reverse equation and you solve it but then i hace 2 many x's and i get all confused, so that's not working and some of the problems on our study guide nothing isny just a number=y its like -5y+3x=-16 and 10y+4x=62 so i cant do that one either how do you solve system of equations?

  • Answer:

    take both the equation -5y+3x=-16 & 10y+4x=62 for the 2nd eq. 10y=62-4x divided by 2 we get 5y=31-2x put last eq. in the 1st -(31-2x)+3x=-16 this implies to x=3 substitute x=3 in the 2nd eq. u will get the value of y

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take both the equation -5y+3x=-16 & 10y+4x=62 for the 2nd eq. 10y=62-4x divided by 2 we get 5y=31-2x put last eq. in the 1st -(31-2x)+3x=-16 this implies to x=3 substitute x=3 in the 2nd eq. u will get the value of y

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