Can you find this Austrian castle? 10 points to whoever finds it?

10 POINTS! TRIGNOMETRY QUESTION on Find the distance between the plane and the airport?

• A plane is flying at an elevation of 21000 feet. It is within sight of the airport and the pilot finds that the angle of depression to the airport is 25degrees. 1. Find the distance between the plane and the airport. 2.Find the distance between a point on the ground directly below the plane and the airport

• Answer:

  Sketches help to understand problems like this. Draw a horizontal line to represent the ground. Erect a perpendicular from the ground. Label the base of this perpendicular G At the top of the perpendicular, mark a dot. This dot is the plane. Label the dot P Somewhere on the ground line, mark another dot . Label it A, for airport. Draw another horizontal line parallel to the ground line, that passes through the point P. Label the ends of this line Y and Z, y being to the left of P. Angle ZPA= 25 degrees Therefore angle GAP also = 25 degrees, (alternate angles) PG / PA=sin25 PG= 21000 Thus 21000 / PA = sin 25 PA=21000 / sin 25 PA= 21000 /0.42262 PA= 49,690 feet, PA being the distance from plane to airport Tan 25=PG/GA .46631=21000 / GA GA= 21000/ .46631 GA=45034 feet