How do you find derivative of natural log function?

The derivative of ln u = u' / u. I like to call this derivative of stuff over stuff. To find the derivative, first look at the x^2ln(x^2). These are two functions multiplied together, so you need to use the product rule: 1st * derivative of 2nd + 2nd * derivative of 1st derivative of x^2 * ln(x^2) = x^2 [2x/x^2] + ln(x^2) [2x] =2x + 2xln(x^2) For the derivative of (lnx)^3 you need to use the power rule and the chain rule. derivative of (lnx)^3 = 3(lnx)^2 [1/x] Combining this all together, we get z' = 2x + 2xln(x^2) + (3/x)(lnx)^2 :)

For the derivative of ln of something first you do 1 over the quantity then multiply it by the derivative of the quantity. So if it's ln(x^2) the derivative is 1/x^2 • 2x

For the derivative of ln of something first you do 1 over the quantity then multiply it by the derivative of the quantity. So if it's ln(x^2) the derivative is 1/x^2 • 2x